Sunday, June 22, 2008

Parametric Parabolas

It hasn't even been a week since we dealt with parabolas, and they come again, this time with actual numbers. The question itself isn't hard, but once again, some thinking is required.

A parabola goes through the points A(17, 3) B(34, z) C(50, -30). B is the maximum point of the parabola. Find point B and the parabola function in standard form.

As you know, a parabola can be written in two ways. One is standard form, with the a, b, and c coefficients, and one is the vertex form. To solve this question, we'll use the vertex form. This form says that the equation a parabola that has a vertex (h, k) is:
y = a(x - h)2 + k

We know h and k, so let's plug them in:
y = a(x - 34)2 + z

We have two other points, so let's use them:
3 = a(17 - 34)2 + z
2 = a(50 - 34)2 + z

3 = 289a + z
-30 = 256a + z

Subtract the second equation from the first:
33 = 33a
a = 1
3 = 289a + z
3 = 289 + z
z = -286

The function of the parabola is:
y = (x - 34)2 - 286

Open parenthese and combine like terms to switch to standard form:
y = x2 - 68x + 1156 - 286
y = x2 - 68x + 870

Nice, isn't it?
Nadav

nadavs

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