Logarithms, or logs, are very useful and powerful tools in mathematics. They can be used for many different problems, and all their properties make them very easy to manipulate.
Today I have another question from Yahoo Answers, but I'll take only the good part:
loga x = c
logb x = d
Find logab x in terms of c and d
This question looks simple. After all, logs have so many properties, there must be one with multiplication of base.
Well, there isn't.
In second thought, there is, but it's not written in any textbook, and to get to it we need to go through many log properties. Shall we start?
First, we can use the log property of reversal of base and argument:
loga x = 1/logx a
Now we can write this for both definitions above:
logx a = 1/loga x = 1/c
logx b = 1/logb x = 1/d
Using the addition property of logs that says: logx ab = logx a + logx b, we can say:
logx ab = 1 / c + 1 / d = d/cd + c/cd = (c + d) / cd.
Now all we need is to reverse the log back to the one we want:
logab x = cd / (c + d)
As you can see, logs don't require too much complicated mathematics, but rather original thinking and creativity.
Do you have any log problems?
Yours,
Nadav
nadavs
Showing posts with label properties of logs. Show all posts
Showing posts with label properties of logs. Show all posts
Sunday, May 18, 2008
Playing with Logarithms
Subscribe to:
Posts (Atom)