After a long dry period, I'm going to publish just one post here, and it contains a riddle for you, without my solution. Today is a very special day for me (well, it's my birthday), so I'm giving you the opportunity to solve something truely difficult.
Use the number 4 twice to get 64.
That's it. Not complicated, yet not very simple. You can use any mathematical operation as long as the final results contains only two 4's. For example, 42 x 4 = 64, but it contains the digit 2, which is unacceptable.
Let's see how long it takes people to solve this, and how old I'll be when it's solved.
The answer is purely mathematic. No word tricks or anything involved.
Post your answers in the comments. Can't wait to see them.
Nadav
nadavs
Thursday, March 18, 2010
The Big Riddle of Four
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10 comments:
Hey its easy : in Roman Text lets write a 4 and beside it another 4 >> IVIV
Now let interchange the V's and I's. It becomes VIIV i.e. a 6 besides a 4 = 64. EASSSSY :-)
It's a math question, not a tricky one.
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